Let the first graders be represented by F, the second graders be represented by S, third graders by T, and fourth graders byFo.
Given data :
\(\frac{S}{Fo} = \frac{8x}{5x}\)
\(\frac{F}{S} = \frac{3y}{4y}\)
\(\frac{T}{Fo} = \frac{3z}{2z}\)
To find a common ratio, we need a common ratio
\(\frac{S}{F} = \frac{16}{10}(When x=2)\)\(\frac{F}{S}= \frac{12}{16}(when y=4)\)
\(\frac{T}{Fo} = \frac{15}{10}(when z=5)\)
The common ratio will be F : S : T : Fo = \(12 : 16 : 15 : 10\) Therefore, the ratio of first graders to third graders is4:5(Option E)
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Given data :
\(\frac{S}{Fo} = \frac{8x}{5x}\)
\(\frac{F}{S} = \frac{3y}{4y}\)
\(\frac{T}{Fo} = \frac{3z}{2z}\)
To find a common ratio, we need a common ratio
\(\frac{S}{F} = \frac{16}{10}(When x=2)\)\(\frac{F}{S}= \frac{12}{16}(when y=4)\)
\(\frac{T}{Fo} = \frac{15}{10}(when z=5)\)
The common ratio will be F : S : T : Fo = \(12 : 16 : 15 : 10\) Therefore, the ratio of first graders to third graders is4:5(Option E)
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