I think the answer is B
1, X=Y-> /x/=3 -> x = 3 or x = -3 -> insufficient
2, y = 3 -> 3x = 9 -> x=3 -> sufficient
1, X=Y-> /x/=3 -> x = 3 or x = -3 -> insufficient
2, y = 3 -> 3x = 9 -> x=3 -> sufficient

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