Bunuel wrote:
\(\frac{5}{(\frac{\sqrt{7}+1}{\sqrt{7}-1})}\)
A.\(40-15\sqrt{7}\)
B.\(40-\frac{\sqrt{7}}{3}\)
C.\(40-\frac{\sqrt{7}}{3}\)
D.\(\frac{125-5\sqrt{7}}{3}\)
E.\(\frac{20-5\sqrt{7}}{3}\)
...
\(\frac{5}{(\frac{\sqrt{7}+1}{\sqrt{7}-1})}\)
A.\(40-15\sqrt{7}\)
B.\(40-\frac{\sqrt{7}}{3}\)
C.\(40-\frac{\sqrt{7}}{3}\)
D.\(\frac{125-5\sqrt{7}}{3}\)
E.\(\frac{20-5\sqrt{7}}{3}\)
...
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