Bunuel wrote:
If x ≠ 0 and \(\frac{1}{x}=\frac{1}{1+\frac{1}{x}}\), then x^2 – x + 4 =
A. 5
B. 4
C. 3
D. 2
E. 1
1/x = x/x+1 i.e; x^2-x-1=0;
We need to find the value of x^2-x+4 i.e; x^2-x-1+5 =0+5 =5
Ans:A
If x ≠ 0 and \(\frac{1}{x}=\frac{1}{1+\frac{1}{x}}\), then x^2 – x + 4 =
A. 5
B. 4
C. 3
D. 2
E. 1
1/x = x/x+1 i.e; x^2-x-1=0;
We need to find the value of x^2-x+4 i.e; x^2-x-1+5 =0+5 =5
Ans:A
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