remainder when 2^86 is divided by 9
= 2^2(43)/9
= 4^43/9
= -5^43/9
now 5 has cyclicity of either 0 or 5, when power is odd , last digit will be 5
Therefore remainder=-5
since it is negative we need to add it to the divisor
therefore remainder= 9-5=4
= 2^2(43)/9
= 4^43/9
= -5^43/9
now 5 has cyclicity of either 0 or 5, when power is odd , last digit will be 5
Therefore remainder=-5
since it is negative we need to add it to the divisor
therefore remainder= 9-5=4
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