Suchilou wrote:
How do you do the simplification?
HiSuchilou
the equation can be written as\(\frac{(x^2y^2-x^2)}{(x+1)(y^2-1)}\)
Tasking\(x^2\) as common, you get\(\frac{x^2(y^2-1)}{(x+1)(y^2-1)}\)
Solve this to get
\(\frac{x^2}{(x+1)}\)
Hence by knowing the value of\(x\) , you can solve the question
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