Bunuel wrote:
If x is a positive number is \(\sqrt{x}\) an integer?
(1) \((x^{(-\frac{1}{4})})^2>1\)
(2) \((x + 1)^2 = (x – 2)^2\)
Statement 1:
(X^ (-1/4))^2 > 1 => X^(-1/2) > 1 => 1/(X^ 1/2) > 1
If 1/ (Something) > 1 => Something must be between 0-1 (something can't be 0, otherwise 1/something will be undefined)
Here Something is X^1/2. So 0<(X^1/2)<1. Hence X^1/2 is not an integer.
Sufficient
Statement 2:
(x + 1)^2 = (x – 2)^2 => X^2 + 2x + 1 = X^2 +
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