Data Sufficiency (DS) | Re: If k does not equal -1, 0 or 1, does the point of intersection of line

If k does not equal -1, 0 or 1, does the point of intersection of line y = kx+b and line x = ky+b have a negative x-coordinate?

We have equations of two lines:\(y = kx + b\) and\(y=\frac{x}{k}-\frac{b}{k}\) (from\(x = ky + b\) ). Equate to get the x-coordinate of the intersection point: \(kx + b=\frac{x}{k}-\frac{b}{k}\) , which gives\(x=\frac{b(k+1)}{1-k^2}=\frac{b(k+1)}{(1-k)(1+k)}=\frac{b}{1-k}\) .

So, the question basically asks whether\(x=\frac{b}{1-k}\) is