Bunuel wrote:
The figure above is a square. What is its area?
(A) 9
(B) 4
(C) 1
(D) 1/4
(E) cannot be determined
[Reveal] Spoiler:
The answer should be D as follows.
The two sides given are x and 3x-1.
since the figure is a squire, both the sides should be equal in length ==> x=3x-1 ==>2x=1 ==>\(x=\frac{1}{2}\) Area of the squire =\(side^2\) ==>\(x^2\) ==>\((\frac{1}{2})^2\) ==>\( \frac{1}{4} \)
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