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Problem Solving (PS) | Re: The formula for the sum of squares of integer between 1 and n is n(

$
0
0
=>

11^2 + 12^2 + … + 20^2
= ( 1^2 + 2^2 + … + 20^2 ) – (1^2 + 2^2 + … + 10^2)
= 20∙21∙41/6 - 10∙11∙21/6
= 2870 – 385
= 2485

Ans: D

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