Problem Solving (PS) | If a square region has area x, what is the length of its diagonal in

Because\(s^2\) = area of asquare:

\(s^2 = x\)
\(s = \sqrt{x}\)

A square's diagonal* is given by\(s\sqrt{2}\)

\(\sqrt{x} * \sqrt{2} = \sqrt{2x}\)
Answer B

*OR use Pythagorean theorem, where hypotenuse = diagonal = d

\((\sqrt{x})^2 + (\sqrt{x})^2 = d^2\)\(2x^2 = d^2\)
\(\sqrt{2x^2} = \sqrt{d^2}\)\(d =\sqrt{2x}\)
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