Bunuel wrote:
Eight dogs are in a pen when a sled owner comes to choose four dogs to form a sled team. If the dogs are to be placed in two rows of two dogs each and different pairings of dogs are considered different teams, how many different sled teams can the owner form?
A. 24
B. 70
C. 210
D. 420
E. 1,680
First we need 4 dogs in total out of eight = 8C4
Now we need to just pick two dogs for the first row so that remaining two dogs will be automatically be selected for other row = 4C2
Total ways = 8C4 *
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