GMATinsight wrote:
6 horses {A,B,C,D,E,F} Participate in a race. If there are no draws in the rate then in how many ways can the race end such that horse A always finishes ahead of C and B both the horses?
A) 720
B) 360
C) 240
D) 120
E) 48
There are four cases:
#1 Horse A finished first (B and C were putarbitrary):
A _ (B) _ (C) _ = all other houses can be arranged in 5! ways = 120
#2 Horse A finished second (and etc.):
_A _ (B) _ (C) = 3C1 for the first place and 2C2*4! For the last 4 places = 3*1*24
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