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Problem Solving (PS) | In the figure above, x^2 + y^2 =

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Mo2men wrote:

genxer123 wrote:
Bunuel wrote:
In the figure above, x^2 + y^2 =

(A) 5
(B) 7
(C) 25
(D) 80
(E) 625
[Reveal] Spoiler:


. . .
The inside triangle is a 3-4-5 right triangle - its hypotenuse is5.

\(x^2 + y^2 = 5\)


The highlighted part should equal to (hypotenuse)...it should be 25.

Mo2men , nice catch. I was thinking of 5 as a fixed value derived from other fixed values, such that 5 =\(c^2\) . I missed a step.

5 =\( (\sqrt{c^2} ) = (\sqrt{5^2} ) =\sqrt{25} \)
...

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