nmargot wrote:
Hi MathRevolution,
I could work out one of the integer the x = 2, however couldn't work out how to get the -3. Where does the the -1 come from in the operation (x-2-1)?
(x−2)2−(x−2)=0=>(x−2)(x−2−1)=0
Thank you,
Nick
Hinmargot
in the expression\((x-2)^2-(x-2)\) , I have taken\((x-2)\) as common
So\((x-2)^2-1*(x-2) = (x-2)(x-2-1)\)
Hope this is clear
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