Data Sufficiency (DS) | If rs ≠ 0, does 1/r + 1/s = 5 ?

\(\frac{1}{r}+\frac{1}{s}=5\) is only possible when both\(r\) and\(s\) are fractions for eg\(r=1\) and\(s=\frac{1}{4}\) or\(r=\frac{1}{2}\) and\(s=\frac{1}{3}\) , if\(r\) &\(s\) are integers then LHS will has a value less than\(1\) .

Statement 1 from this we know\(rs>1\) this implies that r and s are not a proper fraction because the multiplication is greater than 1. Hence LHS cannot be equal to RHS. Sufficient.

Statement 2 \(s<-r\) or\(r+s<0\) . again value of\(r\) &\(s\) cannot be calculated.
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