tarek99 wrote:
As part of a game, four people each must secretly choose an integer between 1 and 4, inclusive. What is the approximate likelihood that all four people will choose different numbers?
A. 9%
B. 12%
C. 16%
D. 20%
E. 25%
Total no. of ways in which the integers can be selected when there is no restriction = 4*4*4*4
Total no. of ways in which the integers can be selected when people have to take different integers = 4*3*2*1
So, percentage = 4*3*2*1 * 100 /(4*4*4*4) = (3/32)*100 = 9.375% ~ 9 %
Answer
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