Psahota wrote:
I think this is a poor-quality question and the explanation isn't clear enough, please elaborate. Hi Team,
In the first statement the answer shows sufficient.
But in case x is Zero then xy will be zero, which is not even.
Hence, how can statement 1 be sufficient?
Please explain
ZERO:
1. 0 is an integer.
2. 0 is an even integer. An even number is aninteger that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.
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