Mo2men wrote:
niks18 wrote:
Bunuel wrote:
Is \(r^x < 100\)?
(1) \(r*\sqrt[3]{x}>100\)
(2) \(x> 1\)
(1) \(r*\sqrt[3]{x}>100\)
(2) \(x> 1\)
Statement 1: if\(r<0\) , then\(x<0\) and if\(r>0\) then\(x>0\)
\(r=-200\) &\(x=-8\) , then\(r*\sqrt[3]{x}\) \(=-200*-2=400>100\)
but\(r^x\) \(= (-200)^{-8} = \frac{1}{(-200)^8}\)\(<100\)
if\(r=200\) and\(x=8\) , then\(r*\sqrt[3]{x}>100\) \(=200*2=400>100\)
but\(r^x=200^8>100\) . Hence insufficient
Statement 2:\(x>\) 1 but nothing given about\(r\) . hence insufficient
Combining 1 & 2 we know that\(x>0\) , hence\(r>0\) so\(r^x>100\) . Hence we get a
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