Problem Solving (PS) | At 1 PM, Ship A leaves port heading due west at x miles per hour. Two

At 1 PM, Ship A leaves port heading due west at x miles per hour. Two hours later, Ship B is 100 miles due south of the same port and heading due north at y miles per hour. At 5 PM, how far apart are the ships?

A.\(\sqrt{(4x)^2 + ( 100 + 2y)^2}\)

B. x + y

C.\(\sqrt{x^2 + y^2}\)

D.\(\sqrt{(4x)^2 + (2y)^2}\)

E.\(\sqrt{(4x)^2 + ( 100 - 2y)^2}\)

Source: NOVA GMAT
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