This sum can be solved using Bayes' Theorem
Lets point out different events.
The event that box B is selected is say A1.
hence P(A1)= 3/10
The event that box C is selected is say A2.
hence P(A2)= 7/10
let D be the event that default is selected in five years.
probability of default in bond B= P(D/A1) = 25%= 1/4
probability of default in bond c= P(D/A2) = 40%= 2/5
Now we are asked to find probability of choosing bond B when default is already selected.
i.e. P(A1/D)=?
According to Bayes's
...
Lets point out different events.
The event that box B is selected is say A1.
hence P(A1)= 3/10
The event that box C is selected is say A2.
hence P(A2)= 7/10
let D be the event that default is selected in five years.
probability of default in bond B= P(D/A1) = 25%= 1/4
probability of default in bond c= P(D/A2) = 40%= 2/5
Now we are asked to find probability of choosing bond B when default is already selected.
i.e. P(A1/D)=?
According to Bayes's
...









