Problem Solving (PS) | Re: What is the smallest of six consecutive odd integers whose average (ar

We can let the first (or smallest) odd integer = n, and thus we have:

n, n + 2, n + 4, n + 6, n + 8, and n + 10 as the six consecutive odd integers.

Since the average of terms in an evenly spaced set is (first number + last number)/2:

(n + n + 10)/2 = x + 2

2n + 10 = 2x + 4

2n = 2x - 6

n = x - 3

Answer: B
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