If a, b, and c are positive, is\(a>\frac{(b+c)}{2}\)
(1) On the number line, a is closer to b than it is to c.
let a=1 , b=2 and c=10 => a is closer to b but average of b and c = \(\frac{(b+c)}{2}\) will be > from a
Let a=10, = and c =1 => => a is closer to b, average of b and c = \(\frac{(b+c)}{2}\) will be < from a
Two conditions
Insufficient
(2) b > c
Clearly insufficient as we don't know anything about a
(1)+(2)
On the number line, a is closer to
...
(1) On the number line, a is closer to b than it is to c.
let a=1 , b=2 and c=10 => a is closer to b but average of b and c = \(\frac{(b+c)}{2}\) will be > from a
Let a=10, = and c =1 => => a is closer to b, average of b and c = \(\frac{(b+c)}{2}\) will be < from a
Two conditions
Insufficient
(2) b > c
Clearly insufficient as we don't know anything about a
(1)+(2)
On the number line, a is closer to
...
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