MadaraU wrote:
IMO its A
a∗b∗c∗d∗e∗f∗g=notzero.
Does a∗b∗c∗d∗e∗f∗g<0 ?
Statement 1
consecutive number are less than 7
6*5*4*3*2*1*-1 = -ve
sufficient
Statement 2
At least one of the numbers is negative
-1*1*2*3*4*5*6 = -ve
-2*-1*1*2*3*4*5 = +ve
Insufficient
The answer should be D.
Here is how statement 2 is sufficient
"-1*1*2*3*4*5*6 = -ve" this is wrong because the 7 numbers are consecutive. with your given example, it will be -1*0*1*2*3*4*5. But here, the product
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