Answer is A
as x,y,z all are positive and x<y, least value of y is 2 and x is 1
I did the following hit and trial
if y=2
Z=3 and x=1...Common factor..1
if y=3
Z=7 and x=1,2...Common factor 1
if y=4
z=25, x=1,2,3..common factor 1
if y=5 z=121..x=1,2,3,4..
if y=6 z=721..x=1,2,3,4,5....CF=1.
Seeing this pattern it is A... I am not able to deduce an algebraic solution but saw this pattern
as x,y,z all are positive and x<y, least value of y is 2 and x is 1
I did the following hit and trial
if y=2
Z=3 and x=1...Common factor..1
if y=3
Z=7 and x=1,2...Common factor 1
if y=4
z=25, x=1,2,3..common factor 1
if y=5 z=121..x=1,2,3,4..
if y=6 z=721..x=1,2,3,4,5....CF=1.
Seeing this pattern it is A... I am not able to deduce an algebraic solution but saw this pattern




