elainetianfong wrote:
niks18 wrote:
Bunuel wrote:
What is the value of x?
(1) x^2 – y^2 = 0
(2) x/y + y/x = 0
(1) x^2 – y^2 = 0
(2) x/y + y/x = 0
Statement 1:\((x-y)(x+y)=0\) , so either\(x-y=0\) or\(x+y=0\) , in either case we have two variables and one equation. henceinsufficient
Statement 2: Solve it to get\(\frac{(x^2+y^2)}{xy}=0\)
or\(x^2+y^2 = 0\) . Sum of two positive numbers is 0 only when both the numbers are 0
Hence\(x=0\) .Sufficient
OptionB
In order to make (2) works, both x, y have to be different from 0.
So, how can x = y = 0 ?
I don't think this is a valid
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