The first chocolate can be distributed to 1 out of 3 children => there are 3 ways to distribute the first chocolate
The second chocolate can be distributed to 1 out of 3 children => there are 3 ways to distribute the second chocolate
The same explanation for 3rd, 4th, 5th, 6th and 7th chocolate
So, there are: 3x3x3x...x3 = 3^7 ways to distribute chocolate. Answer E
Please kudo if it helps. Thanks
The second chocolate can be distributed to 1 out of 3 children => there are 3 ways to distribute the second chocolate
The same explanation for 3rd, 4th, 5th, 6th and 7th chocolate
So, there are: 3x3x3x...x3 = 3^7 ways to distribute chocolate. Answer E
Please kudo if it helps. Thanks



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