Problem Solving (PS) | Re: If x does not equal y, and xy does not equal 0, then when x

\(\frac{x+y}{x-y}\)

If x does not equal y, and xy does not equal 0, then when x is replaced by\(\frac{1}{x}\) and y is replaced by\(\frac{1}{y}\) everywhere in the expression above, the resulting expression is equivalent to:

A) \(-\frac{x+y}{x-y}\)

B) \(\frac{x-y}{x+y}\)

C) \(\frac{x+y}{x-y}\)

D) \(\frac{x^2-y^2}{xy}\)

E) \(\frac{y-x}{x+y}\)