Another quick way to solve the question:
Lets r be the radius of the cercle, and O be the center.
To get the length of "minor arc CD" we need the measure of "Angle COD" and r.
From stmt(1), m+n=60. n and m has the same measure, hence n=30
we now know that CBD is a (30:60:90) right triangle, which hypthenus measure 2*r .
Therefore, CBD has dimensions (r : sqrt(3)*r : 2*r) --- BD=r and CD=sqrt(3)*r
Area of rectangle ABCD is CD* DB= r * sqrt(3)*r = 40. Hence, we find r.
We
...
Lets r be the radius of the cercle, and O be the center.
To get the length of "minor arc CD" we need the measure of "Angle COD" and r.
From stmt(1), m+n=60. n and m has the same measure, hence n=30
we now know that CBD is a (30:60:90) right triangle, which hypthenus measure 2*r .
Therefore, CBD has dimensions (r : sqrt(3)*r : 2*r) --- BD=r and CD=sqrt(3)*r
Area of rectangle ABCD is CD* DB= r * sqrt(3)*r = 40. Hence, we find r.
We
...
.jpg)
