Problem Solving (PS) | If (6 + 2/x)(x - 4) = 0, and x does not equal 4, then x =

\((6 + \frac{2}{x})(x - 4) = 0\)
\((6x - \frac{8}{x} - 24 + 2) = 0\)
\((6x - \frac{8}{x} - 22) = 0\)\(6x^2 - 22x - 8 = 0\)
\(6x^2 - 24x + 2x - 8 = 0\)\(6x(x - 4) + 2(x - 4) = 0\)
\((6x+2)(x-4) = 0 => x=4\) or\(-\frac{1}{3}\)

Since x cannot be 4, the other value of x =\(-\frac{1}{3}\) (Option C)
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