Problem Solving (PS) | Re: If a three digit number ‘xyz’ has 2 factors, how many factors does the

Any six digit number xyzxyz can be re-written as: xyz*1001 or xyz * 7 * 11 * 13 (since 1001 is product of 7, 11, 13)

Now xyz is prime (its given that it has 2 factors only) so this number xyz * 7 * 11 * 13 is now the product of 4 distinct prime numbers. Hence its number of factors = 2*2*2*2 = 16

Hence A answer

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