Problem Solving (PS) | Re: A town's oldest inhabitant is x years older than the sum of the ages

[quote="mustu"] A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets be in 20 years?

A. (J - 50)/3
B. 3(J + 20)/x
C. (J + x - 50)/3
D. (J - x + 60)/3
E. (J + x - 20)/3


think simply

J - 3L = x

or L = (J - x)/3

in 20 years age of each "L" will be
(J - x)/3 + 20

which implies
(J - x + 60)/3

thanks

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