Bunuel wrote:
It costs g cents a mile for gasoline and m cents a mile for all other costs to run a car. How many dollars will it cost to run the car for 100 miles?
(A) (g + m)/100
(B) 100g + 100m
(C) g + m
(D) g + .1m
(E) g
Algebra
\(\frac{gCents}{1mi} +\frac{mCents}{1mi} = \frac{(g+m)Cents}{1mi}\)
\(\frac{(g+m)Cents}{1mi}*100 miles * \frac{1dollar}{100cents}=\)
\((g + m)\)dollars
Answer C
Choose values
Let g = 2 cents
Let m = 2 cents
It costs 2 + 2 = 4 cents per mile to run the car
\( \frac{(4)Cents}{1mi} *100 miles = 400 cents \)
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