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Problem Solving (PS) | If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ?

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Bunuel wrote:

If xy > 0, 1/x + 1/y = 5, and 1/xy = 6, then (x+y)/5 = ?

A.1/25
B.1/6
C.1/5
D.5
E.6

HarrishGowtham wrote:

Answer is B.

(1/X+1/Y)=5 canbe solved as {(x+y)/xy}=6. Substituting for 1/xy=6, we get
x+y=5/6

==> (x+y)/5= 5/(6*5)=1/6.

I am stuck trying to understand this explanation. I got the right answer, but not this way.

\(\frac{1}{x}+ \frac{1}{y} = 5\)
\((\frac{1}{x}+ \frac{1}{y}) = \frac{x + y}{xy}\)
Aren't the two RHS equivalent?

Quote:

(1/X+1/Y)=5 can be solved as {(x+y)/xy}=6.

Can anyone explain the steps from the first part of the above sentence
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