Hey people...another problem I need help with
A tin can 10 cm high contains 500 ml of water, how much would a similar can hold if it were 20 cm high?
Is the answer 1 liter or 2 liters? the book says that since lengths =20/10 the ratio volumes therefore will be equal 2^2/1^2 which =4/1 so the volume of the similar can will be 4X500=2 liters....
How can that be? this is the length we're talking about and not the radius to be squared, right?
A tin can 10 cm high contains 500 ml of water, how much would a similar can hold if it were 20 cm high?
Is the answer 1 liter or 2 liters? the book says that since lengths =20/10 the ratio volumes therefore will be equal 2^2/1^2 which =4/1 so the volume of the similar can will be 4X500=2 liters....
How can that be? this is the length we're talking about and not the radius to be squared, right?