\(\frac{t}{m}\) =\(\frac{3}{2}\) > 3m = 2t > m =\(\frac{2t}{3}\)
\(\frac{t}{(m-10)}\) =\(\frac{2}{1}\)
\(\frac{t}{((2t/3)-10)}\) = 2 > t =\(\frac{4t}{3}\) - 20 > 3t = 4t - 60 > t = 60 (Option D)
...
\(\frac{t}{(m-10)}\) =\(\frac{2}{1}\)
\(\frac{t}{((2t/3)-10)}\) = 2 > t =\(\frac{4t}{3}\) - 20 > 3t = 4t - 60 > t = 60 (Option D)
...
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