Bunuel wrote:
For the sequence \(a_1\), \(a_2\), \(a_3\), … \(a_n\), \(a_n=(a_{n−1})^2–a_{n−2}\). If \(a_1=1\) and \(a_2=0\), what is the sixth term of the sequence?
A. 0
B. 1
C. 2
D. 3
E. 7
Using the formulaabove
\(a_3\) = (0)^2 -1 = -1
\(a_4\) = (-1)^2 -0 = 1
\(a_5\) = (1)^2 -(-1) = 2
\(a_6\) = (2)^2 - (1) = 3
Henceoption D = 3 is the answer and the sixth term.
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