Data Sufficiency (DS) | Re: Is wz(x + y) a negative even integer?

we are looking for 2 things:
1. negative integer
2. this integer must be negative***

statement 1: here no information regarding sign ..............not sufficient.
statement 2: here only sign is given. Z is even. Look at the terms ........wz(x+y).......regardless of the value of x , y and w ...the result will always be even negative.

Thus B is the correct answer.
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