dewdrops909 wrote:
MathRevolution wrote:
=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 1 variable (x) and 0 equations, D is most likely to be the answer. So, we should consider each condition on its own first.
Condition1):
\(x^3+x^2+x = 1\)
\(=> x(x^2+x+1) = 1\)
\(=> x =\frac{1}{(x^2+x+1)}\)
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 1 variable (x) and 0 equations, D is most likely to be the answer. So, we should consider each condition on its own first.
Condition1):
\(x^3+x^2+x = 1\)
\(=> x(x^2+x+1) = 1\)
\(=> x =\frac{1}{(x^2+x+1)}\)
...
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