Problem Solving (PS) | Re: For consecutive integers x, y, and z, where x > y > z,

As we know that x,y and z are consecutive numbers and x > y > z.
I assumed x = y - 1 and z = y + 1

now\(X^2 - Y^2 = (X+Y) (X-Y)\)
= (y-1 +y) (y-1-y)
=-(2y -1)------------------------------------------- (1)

Similarly
\( Y^2 - Z^2 = (Y-Z)\)
...

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