Problem Solving (PS) | Re: If the probability of choosing 2 red marbles without replacement from

Red marbels = 3
Let the number of blue marbels = n
Total marbel = n+3

The ways to choose 2 red marbles without replacement from 3 is 3*2
The ways to choose 2 marbles without replacement from n+3 is (n+3)(n+2)
Hence Probability = 6/(n+3)(n+2) = 3/55
or 2/(n+3)(n+2)
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