Bunuel wrote:
Official Solution:
(1)\(2x^2+9 \lt 9x\) . Factor quadratics:\((x-\frac{3}{2})(x-3) \lt 0\) . The roots are\(\frac{3}{2}\) and 3, the"\(\lt\) " sign indicates that the solution lies between the roots:\(1.5 \lt x \lt 3\) . Since the only integer in this range is 2, then\(x=2\) . Sufficient.
(2)\(|x+10|=2x+8\) . The left hand side (LHS) is an absolute value, which is always non-negative, hence RHS must also be non-negative:\(2x+8 \ge 0\) giving us\(x \ge -4\) . Now, for this range\(x+10\) is
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