GMATPrepNow wrote:
When positive integer N is divided by 18, the remainder is x. When N is divided by 6, the remainder is y. Which of the following are possible values of x and y?
i) x = 9 and y = 3
ii) x = 16 and y = 2
iii) x = 13 and y = 7
A) i only
B) i and ii only
C) i and iii only
D) ii and iii only
E) i,ii and iii
Given, N>0
N = 18k + x
N = 6q + y
Therefore, 18k + x = 6q + y
or x = 6(q-3k) + y
x = Multiple of 6 + y
Check the given statements
i) x = 9 and y = 3, possible for 9 = 6(1) + 3
ii) x =
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