Bunuel wrote:
Chris gave Jane x cards. He gave Betty one card more than he gave Jane and he gave Paul two cards fewer than he gave Betty. In terms of x, how many cards did Chris give Betty, Jane, and Paul altogether?
(A) \(3x + 1\)
(B) \(3x\)
(C) \(3x - 1\)
(D) \(x - 1\)
(E) \(\frac{x}{3}\)
Since the number of cards Chris gave to Jane is x, the number of cards he gave to Betty = x + 1 and the number of cards he gave to Paul = x + 1 - 2 = x - 1.
So the number of cards he gave to these 3 people is:
x + x + 1 + x - 1 = 3x
Answer:
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