mrinalsharma1990 wrote:
gmatzpractice wrote:
x/y * y/z = x/z = -b/(3a)
Is -b/(3a) > 1/2 ?
(1) (a+1)(a-3) = 0
a = -1, 3
Insufficient
(1) (b-1)(b-3) = 0
b = 1, 3
Insufficient
(1) and (2) together:
a = -1; b = 3
-b/(3a) = 1
a = -1; b = 1
-b/(3a) = 1/3
Insufficient
E
Is -b/(3a) > 1/2 ?
(1) (a+1)(a-3) = 0
a = -1, 3
Insufficient
(1) (b-1)(b-3) = 0
b = 1, 3
Insufficient
(1) and (2) together:
a = -1; b = 3
-b/(3a) = 1
a = -1; b = 1
-b/(3a) = 1/3
Insufficient
E
Hi,
I solved by taking a and b common inthe Option (a) and (b)
In option a I got, a(a-2)=3, therefore a=3 or a=5, similarly the values I got for B are -3 and 1, my computing all these 4 values of a & b I got the answer as C.
Please
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