Here's my solution: If one root is 3+2\(\sqrt{3}\), then other root is 3-2\(\sqrt{3}\).
Sum of roots = 6
Product of roots = 9-(4*3) = -3
Hence equation is: \(x^{2}\) - (sum of roots)*x + (product of roots) = \(x^{2}\)- 6x -3
Hence D
Sum of roots = 6
Product of roots = 9-(4*3) = -3
Hence equation is: \(x^{2}\) - (sum of roots)*x + (product of roots) = \(x^{2}\)- 6x -3
Hence D
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