Bunuel wrote:
If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2 - 2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\)
The smallest even integer is x, the next consecutive even integer is (x + 2), and the third consecutive even integer is (x + 4). We can express the product of our 3 integers as:
x(x + 2)(x + 4) = x(x^2 + 6x + 8) = x^3 + 6x^2 + 8x
Answer: A
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