Bunuel wrote:
If x ≠ 2 and \(\frac{(x - 1)(x^2 + 1)}{(x-2)} = 0\), then x =
A. -2
B. -1
C. 1
D. 2
E. 0
The only way for a fractional expression to equal zero is when the numerator is equal to zero. Thus, we can ignore the denominator and set the numerator equal to 0 to solve for x:
(x -1)(x^2 + 1) = 0
x = 1
OR
x^2 +1 = 0
x^2 = -1
Notice that x^2 can never be negative, so x^2 can’t be equal to -1. So x = 1 is the only solution.
Answer: C
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