ishitam wrote:
chetan2u wrote:
rukna wrote:
If each of the sides of a triangle satisfies the equation :-
x^2+18=9x
then the perimeter of the triangle CANNOT be:
A. 9
B. 12
C. 15
D. 18
E. Any of the four values above is possible.
For some reason, I find the fault in question. Can someone please explain. Posted official answer.
x^2+18=9x
then the perimeter of the triangle CANNOT be:
A. 9
B. 12
C. 15
D. 18
E. Any of the four values above is possible.
For some reason, I find the fault in question. Can someone please explain. Posted official answer.
HI,
each sidesatisfies\(x^2+18=9x\)
\(x^2-9x+18=0\) .
\((x-3)(x-6)=0\) .
so x=3 or x=6..
so sides can be 3 or 6...
If all 3, P= 9
if all 6, P = 18
If two sides 6 and third side 3= 2*6+3=15
If two sides
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