GMAT Problem Solving (PS) | A box contains exactly 24 balls, of which 12 are red and 12 are blue.

1st pick: 12 red and 24 total balls, probability of red in 1st pick=

\(\frac{12}{24}\) or\(\frac{1}{2}\)

Now there are 11 red and 23 total balls. (There's no replacement.)

Probability of picking red on the 2nd choice is\(\frac{11}{23}\)

P(2 successive reds) =\( (\frac{1}{2} \)
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